texte à taper dans l'editeur	formule obtenue
\frac{2}{3}	\( \frac{2}{3} \)
E=\{0;1;2\}	\( E=\{0;1;2\} \)
\mathbb{N} \subset \mathbb{R}	\( \mathbb{N} \subset \mathbb{R} \)
-2 \leq x < 3	\( -2 \leq x < 3 \)
\sqrt{2+3\pi}	\( \sqrt{2+3\pi} \)
]1~;~+ \infty[	\( ]1~;~+ \infty[ \)
6 \in A \cap B	\( 6 \in A \cap B \)
6 \notin A \cup B	\( 6 \notin A \cup B \)
\forall x \in \mathbb{R} ; x>0	\( \forall x \in \mathbb{R} ; x>0 \)
P \iff Q	\( P \iff Q \)
\frac{GF}{sin\widehat{H}}=\frac{FH}{sin\widehat{G}}	\( \frac{GF}{sin\widehat{H}}=\frac{FH}{sin\widehat{G}} \)
P(A)=\frac{card(A)}{card\Omega)}	\( P(A)=\frac{card(A)}{card\Omega)} \)
P(\bar{B} \cap C) =\varnothing	\( P(\bar{B} \cap C) =\varnothing \)
\parallel \vec{u} \parallel	\( \parallel \vec{u} \parallel \)
\vec{AB}.\vec{AC}=-1 \times 5+(-5) \times (-3)=10	\( \vec{AB}.\vec{AC}=-1 \times 5+(-5) \times (-3)=10 \)
\alpha \beta \omega \delta \Delta \Omega \theta \Theta \sigma ...	\( \alpha \beta \omega \delta \Delta \Omega \theta \Theta \sigma ... \)
{\Sigma}_{i=1}^{n}	\( {\Sigma}_{i=1}^{n} \)
2 \geq 5	\( 2 \geq 5 \)
\lim\limits_{x \to \infty} e^{x} = + \infty	\( \lim\limits_{x \to \infty} e^{x} = + \infty \)
x = {-b \pm \sqrt{b^2-4ac} \over 2a}	\( x = {-b \pm \sqrt{b^2-4ac} \over 2a} \)